Calculate Lightning Protection for Building

Example: Calculate Whether Lightning Protection is required or not for following Building. Calculate No of Down Conductor for Lightning Protection

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Area of Building / Structure:

  • Length of Building (L) = 60 Meter.
  • Width of Building ( W ) = 28 Meter.
  • Height of Building (H) = 23 Meter.

Lightning Stock Flushing Density

  • Number of Thunderstorm (N)= 80.00 Days/Year
  • Lightning Flash Density   (Ng)=69 km2/Year
  • Application of Structure (A)= Houses & Buildings
  • Type of Constructions (B)= Steel framed encased without Metal Roof
  • Contests or Consequential Effects (C)= Domestic / Office Buildings
  • Degree of Isolation (D)= Structure in a large area having greater height
  • Type of Country (E)= Flat country at any level
  • Maximum Acceptable Overall Risk Factor =0.00000001
Reference Table As per IS:2309
Thunder Storm Days / YearLightning Flash Density (Flashes to Ground /km2/year)
50.2
100.5
201.1
301.9
402.8
503.7
604.7
806.9
1009.2
Application of StructureFactor
Houses & Buildings0.3
Houses & Buildings with outside aerial0.7
Factories / workshop/ Laboratories1
Office blocks / Hotel1.2
Block of Flats / Residences Building1.2
Churches/ Hall / Theaters / Museums, Exhibitions1.3
Departmental stores / Post Offices1.3
Stations / Airports / Stadium1.3
Schools / Hospitals / Children’s Home1.7
Others1.2
Type of ConstructionsFactor
Steel framed encased without Metal Roof0.2
Reinforced concrete without Metal Roof0.4
Steel framed encased with Metal Roof0.8
Reinforced concrete with Metal Roof1
Brick / Plain concrete or masonry without Metal Roof1.4
Timber framed or clad without Metal Roof1.7
Brick / Plain concrete or masonry with Metal Roof2
Timber framed or clad with Metal Roof
Contests or Consequential EffectsFactor
Domestic / Office Buildings0.3
Factories / Workshop0.3
Industrial & Agricultural Buildings0.8
Power stations / Gas works1
Telephone exchange / Radio Station1
Industrial key plants, Ancient monuments1.3
Historic Buildings / Museums / Art Galleries1.3
Schools / hospitals / Children Homes1.7
Degree of IsolationFactor
Structure in a large area having greater height0.4
Structure located in a area of the same height1
Structure completely Isolated2

Calculation:

Collection Area (Ac)=(L x W) + 2 (L x H) + 2(W x H) +(3.14 x H2)

  • Collection Area (Ac) = (60×28)+2x(60×23)+2x(28×23)+(3.14x23x23)
  • Collection Area (Ac) =7389 Meter2

Probable No of Strikes to Building / Structure (P)= Ac x Ng x 10-6 No’s / Year

  • Probable No of Strikes to Building / Structure (P)= 7389x69x106 No’s / Year
  • Probable No of Strikes to Building / Structure (P)= 05098 No’s / Year

Overall Multiplying Factor (M) =A x B x C x D x E

  • Application of Structure (A)= Houses & Buildings as per Table Multiplying Factor = 0.3
  • Type of Constructions (B)= Steel framed encased without Metal Roof as per Table Multiplying Factor =0.2
  • Contests or Consequential Effects (C)= Domestic / Office Buildings as per Table Multiplying Factor =0.3
  • Degree of Isolation (D)= Structure in a large area having greater height as per Table Multiplying Factor =0.4
  • Type of Country (E)= Flat country at any level so as per Table Multiplying Factor =0.3
  • Overall Multiplying Factor (M) =0.3×0.2×0.3×0.4×0.3
  • Overall Multiplying Factor (M) =0.00216

Overall Risk Factor Calculated (xc)= M x P

  • Overall Risk Factor Calculated (xc)= 0.00216 x0.05098
  • Overall Risk Factor Calculated (xc)= 000110127

 Base Area of Structure (Ab) = (LxW)

  • Base Area of Structure (Ab)=60×28
  • Base Area of Structure (Ab)=1680 Meter2

Perimeter of Structure (P) =2x (L+W)

  • Perimeter of Structure (P)=2x(60+28)
  • Perimeter of Structure (P)=176 Meter

Lightning Protection Required or Not

  • If Calculated Overall Risk Factor Calculated > Maximum Acceptable Overall Risk Factor than only Lighting Protection Required
  • Here Calculated Overall Risk Factor is 0.000110127 > Max Acceptable Overall Risk Factor is 00000001
  • Lightning Protection is Required

 No of Down Conductor

  • Down Conductors As per Base Area of Structure (s) =1+(Ab-100)/300
  • Down Conductors As per Base Area of Structure (s) =1+(1680-100)/300
  • Down Conductors As per Base Area of Structure (s) =6 No’s
  • Down Conductors As per Perimeter of Structure (t)= P/30
  • Down Conductors As per Perimeter of Structure (t)= 176/30
  • Down Conductors As per Perimeter of Structure (t)= 6 No’s
  • Minimum No of Down Conductor is 6 No’s

 Results:

  • Lightning Protection is Required
  • Down Conductors As per Base Area of Structure (s) =6 No’s
  • Down Conductors As per Perimeter of Structure (t)= 6 No’s
  • Minimum No of Down Conductor is 6 No’s
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